python convert number to Chinese

Code:

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def num2chinese(num: float or int):
mapping = {
'1': '壹',
'2': '贰',
'3': '叁',
'4': '肆',
'5': '伍',
'6': '陆',
'7': '柒',
'8': '捌',
'9': '玖',
'0': '零',
}
if num == 0:
return mapping['0'] + '元整'
base_unit = {
0: '',
1: '拾',
2: '佰',
3: '仟',
}
unit_integers = {
-1: '',
0: '万',
1: '億',
2: '兆'
}
unit_fractions = {
'0': '',
'1': '角',
'2': '分'
}
max_unit = max(list(unit_integers.keys())) + 1
result = ''
# num = str(float(num)).split('.')
num = str(num).split('.')
if len(num) == 1 or not int(num[1]):
result += unit_fractions['0']
else:
tmp_fraction = num[1]
try:
if int(tmp_fraction[1]):
result += unit_fractions['2']
result += mapping[tmp_fraction[1]]
except IndexError:
pass
if int(tmp_fraction[0]):
result += unit_fractions['1']
result += mapping[tmp_fraction[0]]
if not result:
result += '整'
result += '元'
integers = num[0][::-1]
unit_count = 0
tmp_unit = ''
while True:
tmp = integers[0:4]
if len(tmp) == 0:
break
if int(tmp) == 0:
if unit_count == max_unit:
unit_count = 0
result += unit_integers[max_unit - 1]
tmp_unit = unit_integers[unit_count]
unit_count += 1
else:
result += tmp_unit
break
integers = integers[4:]
base_unit_count = -1
for i in range(0, len(integers), 4):
v = integers[i: i + 4]
continual_zero = True
tmp = ''
is_zero = True
for x in range(len(v)):
if v[x] == '0' and continual_zero:
pass
elif v[x] == '0' and not continual_zero:
tmp += mapping[v[x]]
continual_zero = True
else:
is_zero = False
continual_zero = False
tmp += base_unit[x]
tmp += mapping[v[x]]
if is_zero:
pass
else:
result += (unit_integers[base_unit_count] + tmp)
base_unit_count += 1
base_unit_count %= max_unit
if result[-1] == '元':
return result[2::-1]
return result[::-1]
# python

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